x^2+12=-36-2x^2

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Solution for x^2+12=-36-2x^2 equation: 



x^2+12=-36-2x^2

We move all terms to the left:

x^2+12-(-36-2x^2)=0

We get rid of parentheses

x^2+2x^2+36+12=0

We add all the numbers together, and all the variables

3x^2+48=0

a = 3; b = 0; c = +48;
Δ = b2-4ac
Δ = 02-4·3·48
Δ = -576
Delta is less than zero, so there is no solution for the equation

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